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Forum: BoaterTalk
Re: Help me with math please cherrycreekguide New
Re: Assuming the object did not have any velocity at the lip of the slide... kayakerjim New
Date: Nov 16 2004, 19:15 GMT
From: kayakerjim

	Energy at lip = mgh + (mv^2)/2 Energy at lip = (2000 lbs)(32.2 ft/s^2)(105 ft) + 0 Energy at lip = 6,762,000 lbs ft/s^2 Kinetic energy 2/3 down the slide = 6,762,000 lbs*ft^2/s^2 - (2000 lbs)(32.2 ft/s^2)(2/3)(265 ft)(cos 66.7) Kinetic energy 2/3 down the slide =2,261,747 lbs*ft^2/s^2 Kinetic energy = (1/2)mv^2 2,261,747 lbs*ft^2/s^2 = (1/2)(2000 lbs)v^2 v = 47.6 ft/s v = 32.4 mi/hr (same assumptions - no friction & no starting velocity)

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